要从 TimeDeltaIndex 对象创建 DataFrame,请使用 TimeDeltaIndexto_frame()方法。使用name参数覆盖结果列的名称。
首先,导入所需的库 -
import pandas as pd
创建一个 TimeDeltaIndex 对象。我们已经使用 'data' 参数设置了类似 timedelta 的数据 -
tdIndex = pd.TimedeltaIndex(data =['4 day 8h 20min 35us 45ns', '+17:42:19.999999', '9 day 3h 08:16:02.000055', '+22:35:25.000075'])
显示 TimedeltaIndex -
print("TimedeltaIndex...\n", tdIndex)
从 TimeDeltaIndex 对象创建一个 DataFrame。未使用 'False' 参数在返回的 DataFrame 中设置原始索引。为了覆盖结果列的名称,我们使用了 'name' 参数 -
print("\nTimeDeltaIndex to DataFrame...\n", tdIndex.to_frame(index=False, name = 'DateTimeData'))
以下是代码 -
import pandas as pd # Create a TimeDeltaIndex object # We have set the timedelta-like data using the 'data' parameter tdIndex = pd.TimedeltaIndex(data =['4 day 8h 20min 35us 45ns', '+17:42:19.999999', '9 day 3h 08:16:02.000055', '+22:35:25.000075']) # display TimedeltaIndex print("TimedeltaIndex...\n", tdIndex) # Return a dataframe of the components of TimeDeltas print("\nThe Dataframe of the components of TimeDeltas...\n", tdIndex.components) # Create a DataFrame from TimeDeltaIndex object # The original index isn't set in the returned DataFrame using the 'False' parameter # To override the name of the resulting column, we have used the 'name' parameter print("\nTimeDeltaIndex to DataFrame...\n", tdIndex.to_frame(index=False, name = 'DateTimeData'))输出结果
这将产生以下代码 -
TimedeltaIndex... TimedeltaIndex(['4 days 08:20:00.000035045', '0 days 17:42:19.999999', '9 days 11:16:02.000055', '0 days 22:35:25.000075'], dtype='timedelta64[ns]', freq=None) The Dataframe of the components of TimeDeltas... days hours minutes seconds milliseconds microseconds nanoseconds 0 4 8 20 0 0 35 45 1 0 17 42 19 999 999 0 2 9 11 16 2 0 55 0 3 0 22 35 25 0 75 0 TimeDeltaIndex to DataFrame... Date Time Data 0 4 days 08:20:00.000035045 1 0 days 17:42:19.999999 2 9 days 11:16:02.000055 3 0 days 22:35:25.000075