要将 DateTimeIndex 转换为 Series,请使用方法。DateTimeIndex.to_series()
首先,导入所需的库 -
import pandas as pd
创建一个日期时间索引,周期为 5,频率为 S,即秒。时区是澳大利亚/阿德莱德 -
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5, tz='Australia/Adelaide', freq='40S')
将 DateTimeIndex 转换为系列 -
print("\nDateTimeIndex to series...\n", datetimeindex.to_series())
以下是代码 -
import pandas as pd # DatetimeIndex with period 5 and frequency as S i.e. seconds # timezone is Australia/Adelaide datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5, tz='Australia/Adelaide', freq='40S') # display DateTimeIndex print("DateTimeIndex...\n", datetimeindex) # display DateTimeIndex frequency print("DateTimeIndex frequency...\n", datetimeindex.freq) # Convert DateTimeIndex to Series print("\nDateTimeIndex to series...\n", datetimeindex.to_series())输出结果
这将产生以下代码 -
DateTimeIndex... DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30', '2021-10-18 07:21:12.261811624+10:30', '2021-10-18 07:21:52.261811624+10:30', '2021-10-18 07:22:32.261811624+10:30', '2021-10-18 07:23:12.261811624+10:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='40S') DateTimeIndex frequency... <40 * Seconds> DateTimeIndex to series... 2021-10-18 07:20:32.261811624+10:30 2021-10-18 07:20:32.261811624+10:30 2021-10-18 07:21:12.261811624+10:30 2021-10-18 07:21:12.261811624+10:30 2021-10-18 07:21:52.261811624+10:30 2021-10-18 07:21:52.261811624+10:30 2021-10-18 07:22:32.261811624+10:30 2021-10-18 07:22:32.261811624+10:30 2021-10-18 07:23:12.261811624+10:30 2021-10-18 07:23:12.261811624+10:30 Freq: 40S, dtype: datetime64[ns, Australia/Adelaide]