Python Pandas - 如何以秒频率对 DateTimeIndex 执行地板操作

要以秒频率对 DateTimeIndex 执行地板操作，请使用方法。对于秒频率，使用值为“S”的freq参数DateTimeIndex.floor()

首先，导入所需的库 -

import pandas as pd

创建一个日期时间索引，周期为 7，频率为 S，即秒 -

datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')

显示日期时间索引 -

print("DateTimeIndex...\n", datetimeindex)

以秒频率对 DateTimeIndex 日期进行地板操作。对于秒频率，我们使用了“S” -

print("\nPerforming floor operation with seconds frequency...\n",
datetimeindex.floor(freq='S'))

示例

以下是代码 -

import pandas as pd

# DatetimeIndex with period 7 and frequency as S i.e. seconds
# timezone is Australia/Adelaide
datetimeindex = pd.date_range('2021-10-18 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='40S')

# display DateTimeIndex
print("DateTimeIndex...\n", datetimeindex)

# display DateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)

# getting the second
res = datetimeindex.second

# display only the second
print("\nThe seconds from DateTimeIndex...\n", res)

# Floor operation on DateTimeIndex date with seconds frequency
# For seconds frequency, we have used 'S'
print("\nPerforming floor operation with seconds frequency...\n",
datetimeindex.floor(freq='S'))

这将产生以下代码 -

DateTimeIndex...
DatetimeIndex(['2021-10-18 07:20:32.261811624+10:30',
'2021-10-18 07:21:12.261811624+10:30',
'2021-10-18 07:21:52.261811624+10:30',
'2021-10-18 07:22:32.261811624+10:30',
'2021-10-18 07:23:12.261811624+10:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq='40S')
DateTimeIndex frequency...
<40 * Seconds>

The seconds from DateTimeIndex...
Int64Index([32, 12, 52, 32, 12], dtype='int64')

Performing floor operation with seconds frequency...
DatetimeIndex(['2021-10-18 07:20:32+10:30', '2021-10-18 07:21:12+10:30',
'2021-10-18 07:21:52+10:30', '2021-10-18 07:22:32+10:30',
'2021-10-18 07:23:12+10:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq=None)