Python Pandas - 如何以秒频率舍入 DateTimeIndex

要以秒频率舍入 DateTimeIndex,请使用方法。对于秒频率,使用值为'S'freq参数。DateTimeIndex.round()

首先,导入所需的库 -

import pandas as pd

创建一个日期时间索引,周期为 5,频率为 s 即秒 -

datetimeindex = pd.date_range('2021-09-29 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='28s')

以秒频率对 DateTimeIndex 日期进行舍入操作。对于秒频率,我们使用了“S” -

print("\nPerforming round operation with seconds frequency...\n",
datetimeindex.round(freq='S'))

示例

以下是代码 -

import pandas as pd

# DatetimeIndex with period 5 and frequency as s i.e. seconds
# timezone is Australia/Adelaide
datetimeindex = pd.date_range('2021-09-29 07:20:32.261811624', periods=5,
tz='Australia/Adelaide', freq='28s')

# display DateTimeIndex
print("DateTimeIndex...\n", datetimeindex)

# display DateTimeIndex frequency
print("DateTimeIndex frequency...\n", datetimeindex.freq)

# getting the second
res = datetimeindex.second

# display only the second
print("\nThe second from DateTimeIndex...\n", res)

# Round operation on DateTimeIndex date with seconds frequency
# For seconds frequency, we have used 'S'
print("\nPerforming round operation with seconds frequency...\n",
datetimeindex.round(freq='S'))
输出结果

这将产生以下代码 -

DateTimeIndex...
DatetimeIndex(['2021-09-29 07:20:32.261811624+09:30',
'2021-09-29 07:21:00.261811624+09:30',
'2021-09-29 07:21:28.261811624+09:30',
'2021-09-29 07:21:56.261811624+09:30',
'2021-09-29 07:22:24.261811624+09:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq='28S')
DateTimeIndex frequency...
<28 * Seconds>

The second from DateTimeIndex...
Int64Index([32, 0, 28, 56, 24], dtype='int64')

Performing round operation with seconds frequency...
DatetimeIndex(['2021-09-29 07:20:32+09:30', '2021-09-29 07:21:00+09:30',
'2021-09-29 07:21:28+09:30', '2021-09-29 07:21:56+09:30',
'2021-09-29 07:22:24+09:30'],
dtype='datetime64[ns, Australia/Adelaide]', freq=None)

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