要将 DateTimeIndex 的频率舍入为单个单位的倍数,请使用方法。设置频率的 freq参数。DateTimeIndex.round()
首先,导入所需的库 -
import pandas as pd
DatetimeIndex 周期为 5,频率为 H 即小时 -
datetimeindex = pd.date_range('2021-09-29 07:20:32.261811624', periods=5, tz='Australia/Adelaide', freq='H')
显示日期时间索引 -
print("DateTimeIndex...\n", datetimeindex)
以 10 分钟的频率舍入 DateTimeIndex,即单个单位的倍数。对于分钟频率,我们使用了 'T -
print("\nPerforming round operation with multiples of a single unit frequency...\n", datetimeindex.round(freq='10T'))
以下是代码 -
import pandas as pd # DatetimeIndex with period 5 and frequency as H i.e. hours # timezone is Australia/Adelaide datetimeindex = pd.date_range('2021-09-29 07:20:32.261811624', periods=5, tz='Australia/Adelaide', freq='H') # display DateTimeIndex print("DateTimeIndex...\n", datetimeindex) # display DateTimeIndex frequency print("DateTimeIndex frequency...\n", datetimeindex.freq) # Round a DateTimeIndex with 10 minutes frequency i.e. multiples of a single unit # For minutes frequency, we have used 'T' print("\nPerforming round operation with multiples of a single unit frequency...\n", datetimeindex.round(freq='10T'))输出结果
这将产生以下代码 -
DateTimeIndex... DatetimeIndex(['2021-09-29 07:20:32.261811624+09:30', '2021-09-29 08:20:32.261811624+09:30', '2021-09-29 09:20:32.261811624+09:30', '2021-09-29 10:20:32.261811624+09:30', '2021-09-29 11:20:32.261811624+09:30'], dtype='datetime64[ns, Australia/Adelaide]', freq='H') DateTimeIndex frequency... <Hour> Performing round operation with multiples of a single unit frequency... DatetimeIndex(['2021-09-29 07:20:00+09:30', '2021-09-29 08:20:00+09:30', '2021-09-29 09:20:00+09:30', '2021-09-29 10:20:00+09:30', '2021-09-29 11:20:00+09:30'], dtype='datetime64[ns, Australia/Adelaide]', freq=None)