要返回 Interval 的中点，请使用interval.mid属性。首先，导入所需的库 -
import pandas as pd
使用值为“两者都不是”的“关闭”参数设置打开间隔。开区间（在数学中用方括号表示）不包含其端点，即开区间 [0, 5] 的特征在于条件 0 < x < 5
interval = pd.Interval(5, 20, closed='neither')
显示间隔
print("Interval...\n",interval)返回区间的中点
print("\nThe midpoint for the Interval...\n",interval.mid)以下是代码
import pandas as pd
# Open interval set using the "closed" 带值的参数 "neither"
# 一个开区间（在数学中用方括号表示）不包含它的端点，
# i.e. the open interval [0, 5] is characterized by the conditions 0 < x < 5.
interval = pd.Interval(5, 20, closed='neither')
# 显示间隔
print("Interval...\n",interval)
# 显示间隔 length
print("\nInterval length...\n",interval.length)
# 左边界
print("\nThe left bound for the Interval...\n",interval.left)
# 正确的界限
print("\nThe right bound for the Interval...\n",interval.right)
# 返回区间的中点
print("\nThe midpoint for the Interval...\n",interval.mid)输出结果这将产生以下代码
Interval... (5, 20) Interval length... 15 The left bound for the Interval... 5 The right bound for the Interval... 20 The midpoint for the Interval... 12.5