当弹出窗口完全可见时,将触发shown.bs.popover事件。
首先,使用以下代码在按钮单击上显示弹出窗口-
$(".btn-default").click(function(){ $("[data-toggle='popover']").popover('show'); });
之后,触发popover shown.bs.popover事件并生成警报-
$("[data-toggle='popover']").on('shown.bs.popover', function(){ alert('Popover is completely visible!'); });
您可以尝试运行以下代码来实现show.bs.popover事件-
<!DOCTYPE html> <html> <head> <title>Bootstrap Example</title> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css"> <script src="https://cdn.staticfile.org/jquery/3.3.1/jquery.min.js"></script> <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script> </head> <body> <div class="container"> <a href="#" data-toggle="popover" title="Employee ID" data-content="E001, E004, E008">Awards</a> <div> <p>Here's the list:</p> <button type="button" class="btn btn-default">List</button> </div> </div> <script> $(document).ready(function(){ $(".btn-default").click(function(){ $("[data-toggle='popover']").popover('show'); }); $("[data-toggle='popover']").on('shown.bs.popover', function(){ alert('Popover is completely visible!'); }); }); </script> </body> </html>