如果部分字符串与 R 数据框列中的另一个字符串匹配，要替换总字符串，我们可以按照以下步骤操作 -
首先，创建一个带有字符串列的数据框。
然后，如果部分字符串与另一个字符串匹配，则使用 gsub 函数替换整个字符串。
让我们创建一个数据框，如下所示 -
String<-sample(c("india1234","china1234","russia3541","uk3541","south
africa3541","nepal1234","sri
lanka1234","canada3541","sudan1234","korea1234","belarus3541"),25,replace=TRUE)
df<-data.frame(String)
df输出结果执行时，上述脚本生成以下内容output(this output will vary on your system due to randomization)-
String 1 south\nafrica3541 2 russia3541 3 sudan1234 4 india1234 5 south\nafrica3541 6 india1234 7 south\nafrica3541 8 korea1234 9 korea1234 10 uk3541 11 india1234 12 korea1234 13 belarus3541 14 belarus3541 15 korea1234 16 china1234 17 sudan1234 18 uk3541 19 india1234 20 korea1234 21 korea1234 22 sudan1234 23 uk3541 24 china1234 25 korea1234
如果部分字符串匹配，则替换总字符串
如果字符串中存在 3541，则使用 gsub 函数将总字符串替换为 No，如下所示 -
String<-sample(c("india1234","china1234","russia3541","uk3541","south
africa3541","nepal1234","sri
lanka1234","canada3541","sudan1234","korea1234","belarus3541"),25,replace=TRUE)
df<-data.frame(String)
df$Replaced_S<-gsub(".*3541.*","No",df$String)
df输出结果String Replaced_S 1 china1234 china1234 2 korea1234 korea1234 3 russia3541 No 4 sri\nlanka1234 sri\nlanka1234 5 russia3541 No 6 nepal1234 nepal1234 7 korea1234 korea1234 8 russia3541 No 9 sudan1234 sudan1234 10 sudan1234 sudan1234 11 sudan1234 sudan1234 12 south\nafrica3541 No 13 nepal1234 nepal1234 14 nepal1234 nepal1234 15 south\nafrica3541 No 16 nepal1234 nepal1234 17 canada3541 No 18 sri\nlanka1234 sri\nlanka1234 19 china1234 china1234 20 sudan1234 sudan1234 21 south\nafrica3541 No 22 nepal1234 nepal1234 23 china1234 china1234 24 sri\nlanka1234 sri\nlanka1234 25 china1234 china1234