vector, list, map在遍历时删除符合条件的元素实现方法

直接看源码，内有详细解释

/*
	测试vector, list, map遍历时删除符合条件的元素
	本代码测试环境: ubuntu12 + win7_x64
*/

#include <iostream>
#include <vector>
#include <list>
#include <map>
#include <iterator>

using namespace std;

void Remove1(vector<int> &vec, int num)
{
	for (vector<int>::iterator it = vec.begin(); it != vec.end();)
	{
		if (*it == num)
			it = vec.erase(it);
		else
			it++;
	}
}

void Remove2(list<int> &lst, int num)
{
	list<int>::iterator it;
	for (it=lst.begin(); it!=lst.end();)
	{
		if (*it == num)
		{
			lst.erase(it++);
		}
		else
			it++;
	}
}

void initMap(map<int, int>& m, int arr[], int arrLen)
{
	for(int i = 0; i < arrLen; i++)
		m[i] = arr[i];
}

void Remove_map(map<int, int>& m, int num)
{
	map<int, int>::iterator it;

	for(it = m.begin(); it != m.end();)
	{
		if (it->second == num)
			m.erase(it++);
		else
			it++;
	}
}

void displayMap(map<int, int>& m)
{
	map<int, int>::iterator it = m.begin();
	while(it != m.end())
	{
		cout << "key = " << it->first << ", value = " << it->second << endl;
		it++;
	}
	cout << endl;
}

int main(void)
{
	int arr[] = {1, 3, 5, 5, 5, 13, 7, 5, 7, 9};
	int arrLen = sizeof(arr) / sizeof(arr[0]);

#if 1
	// test vector
	vector<int> vec(arr, arr+arrLen);
	Remove1(vec, 5);
	copy(vec.begin(), vec.end(), ostream_iterator<int>(cout, " "));
	cout << endl << endl;
#endif

	// test list
	list<int> lst(arr, arr+arrLen);
	Remove2(lst, 5);
	copy(lst.begin(), lst.end(), ostream_iterator<int>(cout, " "));
	cout << endl << endl;

	// test map
	map<int, int> m;
	initMap(m, arr, arrLen);
	Remove_map(m, 5);
	displayMap(m);

	return 0;
}

/*
Win7_x64运行结果:
1 3 13 7 7 9

1 3 13 7 7 9

key = 0, value = 1
key = 1, value = 3
key = 5, value = 13
key = 6, value = 7
key = 8, value = 7
key = 9, value = 9

Ubuntu12运行结果:
[zcm@cpp #54]$make
g++ -Wall -Os -DLINUX -o a a.cpp
[zcm@cpp #55]$./a
1 3 13 7 7 9 

1 3 13 7 7 9 

key = 0, value = 1
key = 1, value = 3
key = 5, value = 13
key = 6, value = 7
key = 8, value = 7
key = 9, value = 9

*/

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