实现为LIFO的堆栈,其中插入和删除从同一末端开始。输入的最后一个元素首先被删除。
堆栈操作是-
push(int数据) -在顶部插入
INTpop()
-删除从顶部
被实现为FIFO的队列,其中插入是在一端(后部)完成,而删除是在另一端(前部)完成。输入的第一个元素首先被删除。
队列操作是-
EnQueue(int数据) -在后端插入
INTDeQueue()
-删除从前端
这是一个使用两个队列实现堆栈的C ++程序
Begin function enqueue1 to insert item a at qu1: Set, np1 = new qu1 np1->d1 = a np1->n1 = NULL if (f1 == NULL) Then set r1 = np1 r1->n1 = NULL f1 = r1 else r1->n1 = np1 r1 = np1 r1->n1 = NULL End Begin function dequeue1 to delete item from qu1. if queue is null Print no elements present in queue. Else q1 = f1 f1 = f1->n1 a = q1->d1 delete(q1) return a End Begin function enqueue2 to insert item a at qu2. np2 = new qu2; np2->d2 = a; np2->n2 = NULL; if queue is null Set r2 = np2 r2->n2 = NULL f2 = r2 Else Set r2->n2 = np2 r2 = np2 r2->n2 = NULL End Begin function dequeue2 to delete item from qu2: if queue is null Print no elements present in queue. Else q2 = f2 f2 = f2->n2 a = q2->d2 delete(q2) return a End
#include<iostream> using namespace std; struct qu1// queue1 declaration { qu1 *n1; int d1; }*f1 = NULL, *r1 = NULL, *q1 = NULL, *p1 = NULL, *np1 = NULL; struct qu2// queue2 declaration { qu2 *n2; int d2; }*f2 = NULL, *r2 = NULL, *q2 = NULL, *p2 = NULL, *np2 = NULL; void enqueue1(int a) { np1 = new qu1; np1->d1 = a; np1->n1 = NULL; if (f1 == NULL) { r1 = np1; r1->n1 = NULL; f1 = r1; } else { r1->n1 = np1; r1 = np1; r1->n1 = NULL; } } int dequeue1() { int a; if (f1 == NULL) { cout<<"no elements present in queue\n"; } else { q1 = f1; f1 = f1->n1; a = q1->d1; delete(q1); return a; } } void enqueue2(int a) { np2 = new qu2; np2->d2 = a; np2->n2 = NULL; if (f2 == NULL) { r2 = np2; r2->n2 = NULL; f2 = r2; } else { r2->n2 = np2; r2 = np2; r2->n2 = NULL; } } int dequeue2() { int a; if (f2 == NULL) { cout<<"no elements present in queue\n"; } else { q2 = f2; f2 = f2->n2; a = q2->d2; delete(q2); return a; } } int main() { int n, a, i = 0; cout<<"Enter the number of elements to be entered into stack\n"; cin>>n; while (i < n) { cout<<"enter the element to be entered\n"; cin>>a; enqueue1(a); i++; } cout<<"\n\nElements popped\n\n"; while (f1 != NULL || f2 != NULL)// if both queues are not null { if (f2 == NULL)// if queue 2 is null { while (f1->n1 != NULL) { enqueue2(dequeue1()); } cout<<dequeue1()<<endl; } else if (f1 == NULL)//if queue 1 is null { while (f2->n2 != NULL) { enqueue1(dequeue2()); } cout<<dequeue2()<<endl; } } }
输出结果
Enter the number of elements to be entered into stack 5 enter the element to be entered 1 enter the element to be entered 2 enter the element to be entered 3 enter the element to be entered 4 enter the element to be entered 5 Elements popped 5 4 3 2 1