给定一个字符串,让我们分析多少个字符是元音。
我们首先找出所有单个和唯一字符,然后测试它们是否在表示元音的字符串中存在。
stringA = "Nhooo is best" print("Given String: \n",stringA) vowels = "AaEeIiOoUu" # Get vowels res = set([each for each in stringA if each in vowels]) print("The vlowels present in the string:\n ",res)
输出结果
运行上面的代码给我们以下结果-
Given String: Nhooo is best The vlowels present in the string: {'e', 'i', 'a', 'o', 'u'}
通过将其视为字典,此功能可以从字符串中提取元音。
stringA = "Nhooo is best" #ignore cases stringA = stringA.casefold() vowels = "aeiou" def vowel_count(string, vowels): # Take dictionary key as a vowel count = {}.fromkeys(vowels, 0) # To count the vowels for v in string: if v in count: # Increasing count for each occurence count[v] += 1 return count print("Given String: \n", stringA) print ("The count of vlowels in the string:\n ",vowel_count(stringA, vowels))
输出结果
运行上面的代码给我们以下结果-
Given String: nhooo is best The count of vlowels in the string: {'a': 1, 'e': 1, 'i': 3, 'o': 2, 'u': 1}