给定一个数字,任务是检查输入的数字是否为幸运数字并显示结果。
幸运数字是指每个数字都不相同的数字,如果至少重复一位,则该数字将不被视为幸运数字。
Input-: n = 1234 Output-: it is a lucky number Explanation-: As there is no repeating digit in a number n so it is a lucky number Input-: n = 3434 Output-: it is not a lucky number Explanation-: In the given number n, 3 and 4 are repeating twice so it is not a lucky number
我们在给定程序中使用的方法如下-
从用户输入数字n以检查它是否是幸运数字
遍历整个数字直到一个数字的大小
标记每次访问过的数字,并检查是否已找到
显示给定号码是否为幸运号码
Start Step1-> declare function to check whether a given number is lucky or not bool check_lucky(int size) declare bool arr[10] Loop For int i=0 and i<10 and i++ Set arr[i] = false End Loop While(size > 0) declare int digit = size % 10 IF (arr[digit]) return false End set arr[digit] = true Set size = size/10 End return true Step 2-> In main() Declare int arr[] = {0,34,2345,1249,1232} calculate int size = sizeof(arr)/sizeof(arr[0]) Loop For int i=0 and i<size and i++ check_lucky(arr[i])? print is Lucky : print is not Lucky End Stop
#include<iostream> using namespace std; //如果有数字,则返回true。 bool check_lucky(int size) { bool arr[10]; for (int i=0; i<10; i++) arr[i] = false; while (size > 0) { int digit = size % 10; if (arr[digit]) return false; arr[digit] = true; size = size/10; } return true; } int main() { int arr[] = {0,34,2345,1249,1232}; int size = sizeof(arr)/sizeof(arr[0]); for (int i=0; i<size; i++) check_lucky(arr[i])? cout << arr[i] << " is Lucky \n": cout << arr[i] << " is not Lucky \n"; return 0; }
输出结果
19 is Lucky 34 is Lucky 2345 is Lucky 1249 is Lucky 1232 is not Lucky