给定一个数字，任务是检查输入的数字是否为幸运数字并显示结果。
幸运数字是指每个数字都不相同的数字，如果至少重复一位，则该数字将不被视为幸运数字。
Input-: n = 1234 Output-: it is a lucky number Explanation-: As there is no repeating digit in a number n so it is a lucky number Input-: n = 3434 Output-: it is not a lucky number Explanation-: In the given number n, 3 and 4 are repeating twice so it is not a lucky number
我们在给定程序中使用的方法如下-
从用户输入数字n以检查它是否是幸运数字
遍历整个数字直到一个数字的大小
标记每次访问过的数字，并检查是否已找到
显示给定号码是否为幸运号码
Start
Step1-> declare function to check whether a given number is lucky or not
bool check_lucky(int size)
declare bool arr[10]
Loop For int i=0 and i<10 and i++
Set arr[i] = false
End
Loop While(size > 0)
declare int digit = size % 10
IF (arr[digit])
return false
End
set arr[digit] = true
Set size = size/10
End
return true
Step 2-> In main() Declare int arr[] = {0,34,2345,1249,1232}
calculate int size = sizeof(arr)/sizeof(arr[0])
Loop For int i=0 and i<size and i++
check_lucky(arr[i])?
print is Lucky : print is not Lucky
End
Stop#include<iostream>
using namespace std;
//如果有数字，则返回true。
bool check_lucky(int size) {
bool arr[10];
for (int i=0; i<10; i++)
arr[i] = false;
while (size > 0) {
int digit = size % 10;
if (arr[digit])
return false;
arr[digit] = true;
size = size/10;
}
return true;
}
int main() {
int arr[] = {0,34,2345,1249,1232};
int size = sizeof(arr)/sizeof(arr[0]);
for (int i=0; i<size; i++)
check_lucky(arr[i])? cout << arr[i] << " is Lucky \n": cout << arr[i] << " is not Lucky \n";
return 0;
}输出结果
19 is Lucky 34 is Lucky 2345 is Lucky 1249 is Lucky 1232 is not Lucky