让我们写一个C程序,使用运行时编译来计算5 x 5数组的行和列总和。
在此程序中,我们在运行时在控制台中输入大小为5X5矩阵的array的值,借助for循环,我们尝试添加行和列。
行求和的逻辑在下面给出-
for(i=0;i<5;i++) {//我要排 for(j=0;j<5;j++){ //j是列 row=row+A[i][j]; //计算行总和 }
进行列总和的逻辑是-
for(j=0;j<5;j++){ // j是列 for(i=0;i<5;i++){ //我要排 column=column+A[i][j]; }
#include<stdio.h> void main(){ //Declaring array and variables// int A[5][5],i,j,row=0,column=0; //Reading elements into the array// printf("Enter elements into the array : \n"); for(i=0;i<5;i++){ for(j=0;j<5;j++){ printf("A[%d][%d] : ",i,j); scanf("%d",&A[i][j]); } } //Computing sum of elements in all rows// for(i=0;i<5;i++){ for(j=0;j<5;j++){ row=row+A[i][j]; } printf("The sum of elements in row number %d is : %d\n",i,row); row=0; } //Computing sum of elements in all columns// for(j=0;j<5;j++){ for(i=0;i<5;i++){ column=column+A[i][j]; } printf("The sum of elements in column number %d is : %d\n",i,column); column=0; } }输出结果
Enter elements into the array : A[0][0] : A[0][1] : A[0][2] : A[0][3] : A[0][4] : A[1][0] : A[1][1] : A[1][2] : A[1][3] : A[1][4] : A[2][0] : A[2][1] : A[2][2] : A[2][3] : A[2][4] : A[3][0] : A[3][1] : A[3][2] : A[3][3] : A[3][4] : A[4][0] : A[4][1] : A[4][2] : A[4][3] : A[4][4] : The sum of elements in row number 0 is : 0 The sum of elements in row number 1 is : 9 The sum of elements in row number 2 is : -573181070 The sum of elements in row number 3 is : 4196174 The sum of elements in row number 4 is : -417154028 The sum of elements in column number 5 is : -994596681 The sum of elements in column number 5 is : 65486 The sum of elements in column number 5 is : 1 The sum of elements in column number 5 is : 4196182 The sum of elements in column number 5 is : 4196097