php+ajax+json 详解及实例代码

php+ajax+json 实例代码

html页面：

<html>
<head>
<meta http-equiv="content-type" content="text/html;charset=utf-8" />
<script type="text/javascript" src="jquery-1.8.2.min.js"></script>
<script type="text/javascript">
 $(function(){
   $("#send").click(function(){
    var cont = $("input").serialize();
    $.ajax({
      url:'ab.php',
      type:'post',
      dataType:'json',
      data:cont,
      success:function(data){
       var str = data.username + data.age + data.job;
       $("#result").html(str);
    }
  });
 }); 
 });
</script>
</head>
<body>
<div id="result">一会看显示结果</div>
<form id="my" action="" method="post">
      <p><span>姓名：</span> <input type="text" name="username" /></p>
     <p><span>年龄：</span><input type="text" name="age" /></p>
     <p><span>工作：</span><input type="text" name="job" /></p>
</form>
<button id="send">提交</button>
</body>
</html>

php页面：

<?php
header("Content-type:text/html;charset=utf-8");
    $username = $_POST['username'];
    $age = $_POST['age'];
    $job = $_POST['job'];
    $json_arr = array("username"=>$username,"age"=>$age,"job"=>$job);
    $json_obj = json_encode($json_arr);
    echo $json_obj;
?>

使用post方式

<script type="text/javascript">
 $(function(){
 $("#send").click(function(){
   var cont = {username:$("input")[0].value,age:$("input")[1].value,job:$("input")[2].value};
   var url = 'ab.php';
   $.post(url,cont,function(data){
    var res = eval("(" + data + ")");//转为Object对象
   var str = res.username + res.age + res.job;
  $("#result").html(str);
  });
 }); 
 });
</script>

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