math.acos()方法是数学模块的一种库方法,用于获取反余弦,它接受-1到1之间的数字,并返回给定数字的反余弦值(以弧度为单位)。
注意: math.acos()方法接受-1到1之间的范围内的唯一号码,如果我们提供数超出范围,则返回一个ValueError异常- “ValueError异常:数学领域的错误”,如果我们提供任何其他除外数量,则返回错误类型错误- “ TypeError:需要浮点数”。
它的语法 math.acos() 方法:
math.acos(x)
Parameter(s): x –是要计算其反余弦的数字。
返回值: float-返回一个浮点值,该浮点值是数字x的反余弦值。
示例
Input: a = 0.278 # 函数调用 print(math.acos(a)) Output: 0.2853901924877167
# python代码演示示例 # math.acos() method # 导入数学模块 import math # 数 a = -1 print("acos(",a,") is = ", math.acos(a)) a = 0 print("acos(",a,") is = ", math.acos(a)) a = 0.278 print("acos(",a,") is = ", math.acos(a)) a = 1 print("acos(",a,") is = ", math.acos(a))
输出结果
acos( -1 ) is = 3.141592653589793 acos( 0 ) is = 1.5707963267948966 acos( 0.278 ) is = 1.2890849198520296 acos( 1 ) is = 0.0
ValueError示例
# python代码演示示例 # math.acos() method with an exception # 导入数学模块 import math # 数 a = 2 print("acos(",a,") is = ", math.acos(a))
输出结果
Traceback (most recent call last): File "/home/main.py", line 9, in <module> print("acos(",a,") is = ", math.acos(a)) ValueError: math domain error
TypeError示例
# python代码演示示例 # math.acos() method with an exception # 导入数学模块 import math # 数 a = "2" print("acos(",a,") is = ", math.acos(a))
输出结果
Traceback (most recent call last): File "/home/main.py", line 9, in <module> print("acos(",a,") is = ", math.acos(a)) TypeError: a float is required