假设我们有两个这样的对象数组-
const arr1 = [ {name:'test', lastname: 'test', gender:'f'}, {name:'test1', lastname: 'test1', gender:'f'}, {name:'test2', lastname: 'test2', gender:'m'} ]; const arr2 = [ {name:'test21', lastname: 'test21', gender:'f'}, {name:'test1', lastname: 'test1', gender:'f'}, {name:'test2', lastname: 'test2', gender:'m'}, {name:'test22', lastname: 'test22', gender:'m'} ];
这些数组中没有任何重复的对象(基于“ name”属性重复),但是在第一个和第二个对象中存在一些对象具有重复的名称。
我们需要编写一个JavaScript函数,该函数接受两个这样的数组并返回一个新数组。
新数组应包含第一个数组和第二个数组的所有唯一对象。在这里,要检查任何对象的唯一性,我们将检查其唯一的“名称”属性。
为此的代码将是-
const arr1 = [ {name:'test', lastname: 'test', gender:'f'}, {name:'test1', lastname: 'test1', gender:'f'}, {name:'test2', lastname: 'test2', gender:'m'} ]; const arr2 = [ {name:'test21', lastname: 'test21', gender:'f'}, {name:'test1', lastname: 'test1', gender:'f'}, {name:'test2', lastname: 'test2', gender:'m'}, {name:'test22', lastname: 'test22', gender:'m'} ]; const mergeUniquely = (arr1 = [], arr2 = []) => { const newArr = arr1.concat(arr2); const map = {}; const res = []; newArr.forEach(el => { if(!map[el['name']]){ res.push(el); map[el['name']] = 1; }; }); return res; }; console.log(mergeUniquely(arr1, arr2));
输出结果
控制台中的输出将是-
[ { name: 'test', lastname: 'test', gender: 'f' }, { name: 'test1', lastname: 'test1', gender: 'f' }, { name: 'test2', lastname: 'test2', gender: 'm' }, { name: 'test21', lastname: 'test21', gender: 'f' }, { name: 'test22', lastname: 'test22', gender: 'm' } ]