在循环检查中,对每个元素进行I%2运算的结果,如果元素为0,则元素为偶数,否则元素为奇数。
public class OddNumbersInAnArray { public static void main(String args[]){ int[] myArray = {23, 93, 56, 92, 39}; System.out.println("Even numbers in the given array are:: "); for (int i=0; i<myArray.length; i++){ if(myArray[i]%2 == 0){ System.out.println(myArray[i]); } } System.out.println("Odd numbers in the given array are:: "); for (int i=0; i<myArray.length; i++){ if(myArray[i]%2 != 0){ System.out.println(myArray[i]); } } } }
输出结果
Even numbers in the given array are:: 56 92 Odd numbers in the given array are:: 23 93 39