您可以使用date_format()将varchar转换为日期。语法如下-
SELECT DATE_FORMAT(STR_TO_DATE(yourColumnName, 'yourFormatSpecifier'), 'yourDateFormatSpecifier') as anyVariableName from yourTableName;
为了理解上述语法,让我们创建一个表。创建表的查询如下-
mysql> create table VarcharToDate -> ( -> Id int NOT NULL AUTO_INCREMENT, -> Created_Time varchar(100), -> PRIMARY KEY(Id) -> );
使用insert命令在表中插入一些记录。查询如下-
mysql> insert into VarcharToDate(Created_Time) values('12/1/2016'); mysql> insert into VarcharToDate(Created_Time) values('14/3/2017'); mysql> insert into VarcharToDate(Created_Time) values('15/3/2018'); mysql> insert into VarcharToDate(Created_Time) values('19/5/2011'); mysql> insert into VarcharToDate(Created_Time) values('19/8/2019'); mysql> insert into VarcharToDate(Created_Time) values('21/11/2020');
使用select语句显示表中的所有记录。查询如下-
mysql> select *from VarcharToDate; +----+--------------+ | Id | Created_Time | +----+--------------+ | 1 | 12/1/2016 | | 2 | 14/3/2017 | | 3 | 15/3/2018 | | 4 | 19/5/2011 | | 5 | 19/8/2019 | | 6 | 21/11/2020 | +----+--------------+ 6 rows in set (0.00 sec)
这是将varchar转换为日期的查询。首先,您需要使用str_to_date()函数将其转换为日期。之后,使用date_format()给出实际日期-
mysql> select date_format(str_to_date(Created_Time, '%d/%m/%Y'), '%Y-%m-%d') as Date from VarcharToDate;
以下是输出-
+------------+ | Date | +------------+ | 2016-01-12 | | 2017-03-14 | | 2018-03-15 | | 2011-05-19 | | 2019-08-19 | | 2020-11-21 | +------------+ 6 rows in set (0.00 sec)