假设我们有两个对象数组,其中包含有关公司某些产品的信息-
const first = [ { id: "57e7a1cd6a3f3669dc03db58", quantity:3 }, { id: "57e77b06e0566d496b51fed5", quantity:3 }, { id: "57e7a1cd6a3f3669dc03db58", quantity:3 }, { id: "57e77b06e0566d496b51fed5", quantity:3 } ]; const second = [ { id: "57e7a1cd6a3f3669dc03db58", quantity:6 }, { id: "57e77b06e0566d496b51fed5", quantity:6 } ];
现在,我们需要编写一个合并两个数组的函数,以使具有相同ID的对象不会出现重复的外观,此外,对象重复ID的数量属性将加在一起。
因此,让我们为该函数编写代码-
const first = [ { id: "57e7a1cd6a3f3669dc03db58", quantity:3 }, { id: "57e77b06e0566d496b51fed5", quantity:3 }, { id: "57e7a1cd6a3f3669dc03db58", quantity:3 }, { id: "57e77b06e0566d496b51fed5", quantity:3 } ]; const second = [ { id: "57e7a1cd6a3f3669dc03db58", quantity:6 }, { id: "57e77b06e0566d496b51fed5", quantity:6 } ]; const mergeArray = (first, second) => { return [...first, ...second].reduce((acc, val, i, arr) => { const { id, quantity } = val; const ind = acc.findIndex(el => el.id === id); if(ind !== -1){ acc[ind].quantity += quantity; }else{ acc.push({ id, quantity }); } return acc; }, []); } console.log(mergeArray(first, second));
输出结果
控制台中的输出将为-
[ { id: '57e7a1cd6a3f3669dc03db58', quantity: 12 }, { id: '57e77b06e0566d496b51fed5', quantity: 12 } ]