使用空值JavaScript过滤掉数组中的对象

假设我们有一个有关公司某些员工的对象的数组。但是数组包含一些错误的数据，即指向空字符串或错误值的键。我们的工作是编写一个函数，该函数接受数组并删除名称键具有null或undefined或空字符串值的对象，并返回新对象。

对象数组是这样的-

let data = [{
   "name": "Ramesh Dhiman",
   "age": 67,
   "experience": 45,
   "description": ""
}, {
      "name": "",
      "age": 31,
      "experience": 9,
      "description": ""
}, {
      "name": "Kunal Dhiman",
      "age": 27,
      "experience": 7,
      "description": ""
}, {
      "name": "Raman Kumar",
      "age": 34,
      "experience": 10,
      "description": ""
}, {
      "name": "",
      "age": 41,
      "experience": 19,
      "description": ""
   }
]

让我们为该函数编写代码-

示例

let data = [{
   "name": "Ramesh Dhiman",
   "age": 67,
   "experience": 45,
   "description": ""
}, {
      "name": "",
      "age": 31,
      "experience": 9,
      "description": ""
}, {
      "name": "Kunal Dhiman",
      "age": 27,
      "experience": 7,
      "description": ""
}, {
      "name": "Raman Kumar",
      "age": 34,
      "experience": 10,
      "description": ""
}, {
      "name": "",
      "age": 41,
      "experience": 19,
      "description": ""
   }
]
const filterUnwanted = (arr) => {
   const required = arr.filter(el => {
      return el.name;
   });
   return required;
};
console.log(filterUnwanted(data));

输出结果

控制台中的输出将为-

[
   { name: 'Ramesh Dhiman', age: 67, experience: 45, description: '' },
   { name: 'Kunal Dhiman', age: 27, experience: 7, description: '' },
   { name: 'Raman Kumar', age: 34, experience: 10, description: '' }
]