这里给出了两个字符串,首先我们必须从第一个字符串中删除所有公共元素,并且第二个字符串的不常见字符必须与第一个字符串的不常见元素连接在一起。
Input >> first string::AABCD Second string:: MNAABP Output >> CDMNP
Uncommonstring(s1,s2) /* s1 and s2 are two string */ Step 1: Convert both string into set st1 and st2. Step 2: use the intersection of two sets and get common characters. Step 3: now separate out characters in each string which are not common in both string. Step 4: join each character without space to get a final string.
# Concatination of two uncommon strings def uncommonstring(s1, s2): # convert both strings into set st1 = set(s1) st2 = set(s2) # take intersection of two sets to get list of common characters lst = list(st1 & st2) finallist = [i for i in s1 if i not in lst] + \ [i for i in s2 if i not in lst] print("CONCATENATED STRING IS :::", ''.join(finallist)) # Driver program if __name__ == "__main__": s1 =input("Enter the String ::") s2=input("Enter the String ::") uncommonstring(s1,s2)
输出结果
Enter the String ::abcde Enter the String ::bdkl CONCATEATED STRINGIS ::: acekl