给定两个用户输入矩阵。我们的任务是显示两个矩阵的加法。在这些问题中，我们综合使用嵌套列表。
Step1: input two matrix. Step 2: nested for loops to iterate through each row and each column. Step 3: take one resultant matrix which is initially contains all 0. Then we multiply each row elements of first matrix with each elements of second matrix, then add all multiplied value. That is the value of resultant matrix.
# Program to multiply two matrices
A=[]
n=int(input("Enter N for N x N matrix: "))
print("Enter the element ::>")
for i in range(n):
row=[] #temporary list to store the row
for j in range(n):
row.append(int(input())) #add the input to row list
A.append(row) #add the row to the list
print(A)
# [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
#Display the 2D array
print("Display Array In Matrix Form")
for i in range(n):
for j in range(n):
print(A[i][j], end=" ") print() #new line
B=[]
n=int(input("Enter N for N x N matrix : ")) #3 here
#use list for storing 2D array
#get the user input and store it in list (here IN : 1 to 9)
print("Enter the element ::>")
for i in range (n):
row=[] #temporary list to store the row
for j in range(n):
row.append(int(input())) #add the input to row list
B.append(row) #add the row to the list
print(B)
# [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
#Display the 2D array
print("Display Array In Matrix Form")
for i in range(n):
for j in range(n):
print(B[i][j], end=" ") print() result = [[0,0,0], [0,0,0], [0,0,0]]
for i in range(len(A)):
for j in range(len(B[0])):
for k in range(len(B)):
result[i][j] += A[i][k] * B[k][j]
print("The Resultant Matrix Is ::>")
for r in result:
print(r)输出结果
Enter N for N x N matrix: 3 Enter the element ::> 2 1 4 2 1 2 3 4 3 [[2, 1, 4], [2, 1, 2], [3, 4, 3]] Display Array In Matrix Form 2 1 4 2 1 2 3 4 3 Enter N for N x N matrix : 3 Enter the element ::> 1 2 3 4 5 6 7 8 9 [[1, 2, 3], [4, 5, 6], [7, 8, 9]] Display Array In Matrix Form 1 2 3 4 5 6 7 8 9 The Resultant Matrix Is ::> [34, 41, 48] [20, 25, 30] [40, 50, 60]