以下是使用迭代查找斐波那契数列的示例。
#include <iostream> using namespace std; void fib(int num) { int x = 0, y = 1, z = 0; for (int i = 0; i < num; i++) { cout << x << " "; z = x + y; x = y; y = z; } } int main() { int num; cout << "Enter the number : "; cin >> num; cout << "\nThe fibonacci series : " ; fib(num); return 0; }
输出结果
Enter the number : 10 The fibonacci series : 0 1 1 2 3 5 8 13 21 34
在上述程序中,实际代码存在于函数fib()中,以计算斐波那契数列。
void fib(int num) { int x = 0, y = 1, z = 0; for (int i = 0; i < num; i++) { cout << x << " "; z = x + y; x = y; y = z; } }
在main()函数中,用户输入数字。调用函数fib(),并按如下所示打印fibonacci系列-
cout << "Enter the number : "; cin >> num; cout << "\nThe fibonacci series : " ; fib(num);