在这个问题上,我们得到一个矩阵。我们的任务是创建一个程序来打印上三角和下三角的总和。
M00 0 0 … 0 M10 M11 0 … 0 M20 M21 M22 … 0 … Mrow0 Mrow1 Mrow2 … Mrow col
M00 M01 M02 … M0col0 M11 M12 … M1col0 0 M22 … M2col… 0 0 0 … Mrow col
Input: {{5, 1, 6} {8, 2, 0} {3, 7, 4}} Output: upper triangle sum = 18 lower triangle sum = 29 Explanation: Sum of upper triangle sum = 5 + 1 + 6 + 2 + 0 + 4 = 18 Sum of lower triangle sum = 5 + 8 + 2 + 3 + 7 + 4 = 29
这个问题的简单解决方案。我们将使用循环遍历上三角元素和下三角元素中的数组。计算两个单独变量lSum和uSum的总和。
该程序说明了我们解决方案的工作原理,
#include <iostream> using namespace std; int row = 3; int col = 3; void sum(int mat[3][3]) { int i, j; int uSum = 0; int lSum = 0; for (i = 0; i < row; i++) for (j = 0; j < col; j++) { if (i <= j) { uSum += mat[i][j]; } } cout<<"Sum of the upper triangle is "<<uSum<<endl; for (i = 0; i < row; i++) for (j = 0; j < col; j++) { if (j <= i) { lSum += mat[i][j]; } } cout<<"Sum of the lower triangle is "<<lSum<<endl; } int main() { int mat[3][3] = { { 5, 1, 6 }, { 8, 2, 0 }, { 3, 7, 4 }}; sum(mat); return 0; }
输出结果
Sum of the upper triangle is 18 Sum of the lower triangle is 29